Answer:
±12.323
Step-by-step explanation:
A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of 238 graduating seniors and found the mean score to be 493 with a standard deviation of 97. Calculate the margin of error using the given formula. How could the results of the survey be made more accurate?
The formula for margin of Error =
±z × Standard deviation/√n
We are not given the confidence interval but let us assume the confidence interval = 95%
Hence:
z score for 95% confidence interval = 1.96
Standard deviation = 97
n = random number of samples = 238
Margin of Error = ± 1.96 × 97/√238
Margin of Error = ±12.323
well first you have to get x and y on separate sides so subtract x by both sides to put x on the right side.
now you have y = 5 - x
to graph that let's throw in some numbers for x and y and make a function table
x, y
1, 4
2, 3
3, 2
4, 1
5, 0
6, -1
and so forth
as you can see as x increases in value, y decreases in value
all you have to do now is plot those points on a graph
X=6 because you add the two like segments of AB and BC together to get 6x-8=28. So then you add the 8 to both sides and get 6x=36 and divide by 6 to get x=6.
X=1 y =2 check your answer a by plugging that in so 1 +2 times 2 = 5 5 times 1 -2 = 3 you just have to find what numbers work