Answer:
its A increases as x goes to ∞
decreases as x goes to -∞
Step-by-step explanation:


- <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

- <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>


According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.
<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>





<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>
The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

Answer:
3 3/10
Step-by-step explanation:
Step 1: Convert 2 4/5 to improper
2 4/5 = 14/5
Step 2: Rewrite
14/5 + 1/2
Step 3: Find common denominator
14/5(2/2) + 1/2(5/5)
28/10 + 5/10
Step 4: Add
33/10
Step 5: Simplify
3 3/10
Answer:
Well if you see the graph (-5, -5) is a total negative number that is in the 3 quadrant.
As for (-9,2) it goes to negative to positive.
Look at the graph and you will understand any questions ask me
hope this helps ☺