Can you please help me.

Mathematics

1 answer:

diamong [38]3 years ago

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Yes, What is your question?

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if two angles are supplementary an one of them is 30 degrees what is the measurement of the second angle

Dafna11 [192]

Supplementary angles always add up to 180. So you need to subtract 30 from 180. Which would give you 150. So 150 is your answer!

6 0

3 years ago

Read 2 more answers

Sin ^6x-cos^6÷1-sin^2x*cos^2x=1-2cos^2x<br><br>

lilavasa [31]

Answer:

$\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x } =1-2\cos^{2} x$ proved.

Step-by-step explanation:

We have to prove that $\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x } =1-2\cos^{2} x$

So, the left hand side = $\frac{\sin^{6} x-\cos^{6}x }{1-\sin^{2}x \cos^{2}x }$

= $\frac{(\sin^{2}x-\cos^{2} x )(\sin^{4} x+\cos^{4}x+\sin^{2}x \cos^{2}x) }{{1-\sin^{2}x \cos^{2}x }}$ {Since we have the formula $a^{3} -b^{3}= (a-b) (a^{2} +ab+b^{2} )$ }

= $\frac{(\sin^{2}x-\cos^{2} x )[(\sin^{2}x+\cos^{2}x )^{2}-2\sin^{2}x\cos^{2} x+ \sin^{2}x\cos^{2} x ]}{{1-\sin^{2}x \cos^{2}x }}$ {Since we have the formula $a^{2}+b^{2} = (a+b)^{2} -2ab$ }