P=2x+2y, y=(p-2x)/2
a=xy, using y found above in this equation gives you:
a=(px-2x^2)/2 we are told a=12 and p=16 so
12=(16x-2x^2)/2
24=16x-2x^2
2x^2-16x+24=0
2x^2-12x-4x+24=0
2x(x-6)-4(x-6)=0
(2x-4)(x-6)=0
2(x-2)(x-6)=0
So the table is 2 ft by 6 ft.
Answer:
The probability is 
Step-by-step explanation:
If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:
If k=1

Because, in her first try she has n possibles options and just one give her a successful login.
If k=2

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.
If k=3

Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.
Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n
Answer:
23.5, 23, 13, 12.5
Step-by-step explanation:
Answer: 8n
Step-by-step explanation: 5n + 3n