Answer:
1. AA
2. SSS
3. I´m not sure about this one, I´m sorry
4. Not similar
Step-by-step explanation:
This photo can help you identify!! I hope this helps
Answer:
492.99
Step-by-step explanation: x = amount invested at 12%
y = amount invested at 9%
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x + y = 20287
0.12x = 0.09y + 492.99
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put the system of linear equations into standard form
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x + y = 20287
0.12x - 0.09y = 492.99
Taking the derivative of 7 times secant of x^3:
We take out 7 as a constant focus on secant (x^3)
To take the derivative, we use the chain rule, taking the derivative of the inside, bringing it out, and then the derivative of the original function. For example:
The derivative of x^3 is 3x^2, and the derivative of secant is tan(x) and sec(x).
Knowing this: secant (x^3) becomes tan(x^3) * sec(x^3) * 3x^2. We transform tan(x^3) into sin(x^3)/cos(x^3) since tan(x) = sin(x)/cos(x). Then secant(x^3) becomes 1/cos(x^3) since the secant is the reciprocal of the cosine.
We then multiply everything together to simplify:
sin(x^3) * 3x^2/ cos(x^3) * cos(x^3) becomes
3x^2 * sin(x^3)/(cos(x^3))^2
and multiplying the constant 7 from the beginning:
7 * 3x^2 = 21x^2, so...
our derivative is 21x^2 * sin(x^3)/(cos(x^3))^2
19. 5x - 5 = 3x -9
2x = -4
x = -2
19. Answer is A
Answer:
21 students pass
Step-by-step explanation:
Firstly, you can set up the problem into an equation where the variable X would equal the number of students passing. You put X over the total number of students in the class, turning it into a fraction, then set it equal to the fraction
(which is 75% represented as a fraction).

The fraction
can be simplified, because 75 and 100 are both multiples of 25, so after canceling out the 25s you would be left with
.

Next, you use the process of cross multiplication which is essentially just multiplying the denominators of both fractions (which would be 28 and 4 in this case) to each side of the equation.

The denominators cancel out leaving you with a simple equation to simplify.


Finally, divide both sides by four in order to isolate the variable.

X = 21.