To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
The answer is 12.50 and equation is y=5.25p -3.25
Answer:
Solution given:
South distance :base[b]=80milea
East distance :perpendicular [p]=35miles
Now
<S=?
we have
=24°
24° bearing should be taken from south airport to East airport.
Answer:
three over three is simplified to be the value 1
Step-by-step explanation:
your answer is 1