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patriot [66]
3 years ago
12

Explain how raising a quotient to a power is similar to raising a product to a power.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0
In your question where to explain how the raising a quotient to power is similar to raising a product to a power. Form me the best explanation to this statement is because the variable with a exponent of positive is equals to its exponent over its variable.
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IS THIS RIGHT OH NO
OverLord2011 [107]

Answer:

the top are right im not sure about bottom

7 0
2 years ago
What is 1500000000000 in scientific notation
omeli [17]
1500000000000 in scientific notation is 
1.5 * 10^12
That is because you move the decimal point 12 places to the left for it to become 1.5.
1.5 * 10^12
move the decimal point 12 places to the right and you got the original number, 1500000000000.

Hope this helps!
5 0
3 years ago
Read 2 more answers
Triangle BAC was rotated 90° clockwise and dilated at a scale factor of 2 from the origin to create triangle XYZ. Based on these
ANEK [815]

Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

A(-4, 4), C(-1, 3), B(-4, 0)

The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

8 0
3 years ago
Read 2 more answers
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
If h(x) = (fºg)(x) and h(x)= 5(x+1)^3 find one possibility for f (x) and g(x).
viktelen [127]

Answer:

One possibility is that;

g(x) = (x + 1)

while h(x) = 5x^3

Step-by-step explanation:

Here, we are told to find one possibility for f(x) and g(x)

The term h(x) = (Fog)(x) means that we are inserting g(x) into f(x) to give h(x)

Now let’s have it this way;

We can see that g(x) = (x + 1) , then h(x) = 5x^3

This is one possibility of the values of g(x) and h(x)

6 0
3 years ago
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