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GalinKa [24]
3 years ago
13

Please help answering questions 215 and 216.

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Problem 215

Check out the attached image. Line up the letters ABC and CDE so the first set of letters are over the second set of letters. Order is important here. Note how A corresponds to C (second C), B corresponds to D, and (the first) C corresponds to E.

We have this mapping:

A <--> C

B <--> D

C <--> E

This means...

Angle BAC corresponds to Angle DCE (red angles)

Angle ABC corresponds to Angle CDE (blue angles)

Angle BCA corresponds to Angle DEC (green angles)

It also means...

Side BC corresponds to Side DE (red sides)

Side AC corresponds to Side CE (blue sides)

Side AB corresponds to Side CD (green sides)

Check out the attached image which I hope clears up any confusion you may have. Often I think it helps to represent stuff like this in a visual way.

============================================

Problem 216

Answer: True

Since triangle ABC is congruent to triangle DEF, this means that side AB is congruent to side ED. These are corresponding sides. Since AB = 6, this means ED = 6 as well.

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$9.35

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Complete question :

Image relating to the question can be found in the attachment below :

Answer:

4/9

Step-by-step explanation:

From the picture :

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What is the GCF of 24 and 40
nikitadnepr [17]

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Using addition formula solve tan 15​
salantis [7]

Answer:

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Step-by-step explanation:

Using the addition formula for tangent

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= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

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3 0
3 years ago
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