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s2008m [1.1K]
3 years ago
8

What is the domain and range and when is it decreasing?

Mathematics
1 answer:
Alla [95]3 years ago
8 0
The Domain is the left most part of the line to the right most part of the line (the most negative x, to the most positive x). 

The Range is the bottom most part of the line to the top most part of the line (the most negative y, to the most positive y).

Domain - [0,12]
Range - [-2,4]
It starts decreasing at (0,4) and stops decreasing at (3,-2)

Hope I helped!
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Determine the projection of w onto u.
irina [24]

Answer:

A.6.2i-4.2 j

Step-by-step explanation:

We are given that

u=9i-6j

v=-3i-2j

w=19i+15j

We have to find the projection of w on to u.

The project of vector a on b

=\frac{a\cdot b}{\mid b\mid^2}b

w.u=(19i+15j)\cdot (9i-6j)=171-90=81

\mid u\mid=\sqrt{x^2+y^2}=\sqrt{9^2+(-6)^2}=\sqrt{117}

Using the formula

The projection of w on to u

=\frac{u\cdot w}{\mid u\mid^2}(u)=\frac{81}{117}(9i-6j)

The projection of w on to u=6.2i-4.2j

Hence, option A is true.

4 0
3 years ago
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nasty-shy [4]
Answer: B. False
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Hope it helped!
8 0
4 years ago
Hi!! Please help me! Need answers with explanation! 15 points!
olganol [36]

Answer:

1. Simplify the expression.

29m - 15

_______

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Step-by-step explanation:

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ivann1987 [24]

Answer: 12

Step-by-step explanation:

<em>Although you have not included which value is the hypotenuse or if they are legs, I will assume the hypotenuse is 20, due to the triangle appearing to be a multiple of the standard 3-4-5 triangle.</em>

The pythagorean theorem is a^2+b^2=c^2, where a and b are the legs and c is the hypotenuse.  Thus, plug in the values to get:

16^2+b^2=20^2

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