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Fofino [41]
4 years ago
10

!HELP!

Mathematics
1 answer:
atroni [7]4 years ago
5 0

I hope this help you with what you need

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Prove 2/sqrt3cosx+sinx=sec(pi/6-x)
dlinn [17]

Thus L.H.S = R.H.S that is 2/√3cosx + sinx  = sec(Π/6-x) is proved

We have to prove that

2/√3cosx + sinx  = sec(Π/6-x)

To prove this we will solve the right-hand side of the equation which is

R.H.S = sec(Π/6-x)

          = 1/cos(Π/6-x)

[As secƟ = 1/cosƟ)

           = 1/[cos Π/6cosx + sin Π/6sinx]

[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]

           = 1/[√3/2cosx + 1/2sinx]

            = 1/(√3cosx + sinx]/2

            = 2/√3cosx + sinx

    R.H.S = L.H.S

Hence 2/√3cosx + sinx  = sec(Π/6-x) is proved

Learn more about trigonometry here : brainly.com/question/7331447

#SPJ9

5 0
1 year ago
If a bottle of water has a mass of about 1 kilogram, about how much mass will it have after someone drinks 500 grams of water fr
Verizon [17]
0.5 kg or 500 grams just simple quest
5 0
4 years ago
Draw quick picture to show how to subtract 314 and 546
dsp73
    5 4 6
 -  3 1 4
_______

6 0
3 years ago
Read 2 more answers
Write a recursive formula for the sequence 7, 12, 17, 22, 27
san4es73 [151]

Answer:

General term

=

n

t

h

t

e

r

m

=

a

n

=

5

n

+

2

Explanation:

Here,

7

,

12

,

17

,

22

,

27

,

...

is an Arithmetic Sequence.

The

,

n

t

h

term of Arithmetic Sequence is :

a

n

=

a

1

+

(

n

−

1

)

d

,

w

h

e

r

e

,

a

1

=

first term and

d

=

common difference

We have,

a

1

=

7

and

d

=

12

−

7

=

17

−

12

=

...

=

5

So,

a

n

=

7

+

(

n

−

1

)

⋅

5

a

n

=

7

+

5

n

−

5

a

n

=

5

n

+

2

Hence,

General term

=

n

t

h

t

e

r

m

=

a

n

=

5

n

+

2

Step-by-step explanation:

7 0
3 years ago
Pls explain how to do this will give brainliest to best answer
Delicious77 [7]

Answer:

1st Graph:

Add all the numbers (Do the same to 2nd Graph)

Then add

answer will be shown

5 0
3 years ago
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