Answer:
The probability that the cost for someone's dog is higher than for the cat is 33.2%.
Step-by-step explanation:
With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.
To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).
Then we have to calculate z, and look up in a standarized normal distribution table.
Calculate z:

The probability of the difference being higher than 0, we have:

We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.
First answer is -5.
Second answer is -1.
Subtract 2x. (It would look like 4y=-2x+10
The answer to your question is
24
H=-3x^2-6x+5 subtract 5 from both sides
h-5=-3x^2-6x divide both sides by -3
(5-h)/3=x^2+2x halve the linear coefficient, square it, add it to both sides....
(2/2)^2=1 add 1 to both sides...
(5-h+3)/3=x^2+2x+1, now the right side is a perfect square...
(8-h)/3=(x+1)^2 multiply both sides by 3
8-h=3(x+1)^2 divide both sides by -1
h-8=-3(x+1)^2 add 8 to both sides
h=-3(x+1)^2+8
h(x)= -3(x+1)^2+8
Second answer down from the top :)