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3 years ago

What words most commonly translate into an equal sign? Use a complete sentence to answer the question.

Mathematics

2 answers:

Anna [14]3 years ago

8 0

Answer:

Two multiplied by three is equal to six

r-ruslan [8.4K]3 years ago

6 0

If an expression has to be written in the form of equation ,then we use equal to sign.

For, example

⇒ The sum of a number 4, and 2 times a number is 6.Find the number.

Answer

Writing in the form of equation we will use equal to sign

Let the number be x.

→4 +2x=6----Here we have used equal to sign, while writing expression in equation form.

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44=2 to the second power times n

nikitadnepr [17]

The solve for n would be 11
2 to the second power is 4 and 4x11=44

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4 years ago

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I need help figuring out which two grids have the same % please

tigry1 [53]

Answer:

a and c

Step-by-step explanation:

The first one is 3/6 = 50%

The second one is 3/8 = 37.5%

The third one is 2/4 = 50%

The fourth one is 5/8 = 62.5%

The ones with the same percent shaded are the first and third

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3 years ago

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Billings printings 1993 sales were what percent of its 1989 sales?

Ronch [10]

Usually it’s around the percentage of about forty five percent

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3 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

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4 years ago

Write the slope-intercept form of the equation that passes through the point (4,-6) and is parallel to the line y = -3/4x - 5

Karolina [17]

The equation that runs through the location (4,-6) has the slope-intercept form, $y=-\frac{3}{4}x-3$ .