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Yuki888 [10]
3 years ago
8

0.402,0.42,0375,12 Order from least yo greatest

Mathematics
1 answer:
Neko [114]3 years ago
6 0

Answer:

0.402, 0.42, 12, 375

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How much greater is the volume of a cube when the length of each edge is multiplied by 3?
snow_lady [41]
3 x 3 x 3 = 27

Answer : 27 times greater.

Hope this helps. - M
6 0
3 years ago
The price of one share of XYZ inc's stock drop by $0.02 on Monday. On Tuesday the price goes back up by $0.05.
Vsevolod [243]

Answer:

1.<u> </u>$(x+0.03) - $x

2. $ 34.21

Step-by-step explanation:

Let the price of XYZ inc's share to be = <u>$ x</u>

On Monday, the price drops by $ 0.02 = $ x- $ 0.02 = $ (x-0.02)

New price of shares on Monday is =<u> $ (x- 0.02)</u>

On Tuesday the price goes up by $0.05 = $ (x-0.02) + $ 0.05 = $(x-0.02+0.05)

New price on Tuesday = <u>$( x+ 0.03)</u>..............................................(a)

Change in price of one share of XYZ's stock= Price on Tuesday - price of share

                                         = <u> $(x+0.03) - $x</u>..........................................(b)

2. Give that x= $34.18  solve equation (a) above

Price on Tuesday at close of business= $ (x+0.03)

                                                               = $ (34.18+0.03)

                                                                = $ 34.21

5 0
3 years ago
32^2+42^2<br> pts 4fre<br> yes im aware i spelled it wrong.
Dima020 [189]

Answer:

2788

Step-by-step explanation:

To square a number means to multiply it by itself:

32^2+42^2=32 \times 32+42 \times 42=1024+1764=2788

7 0
3 years ago
Jose paid $36.40 for 4 movie tickets. Each ticket costs the same amount. What was the cost of the movie tickets in dollars and c
Keith_Richards [23]

Answer:

$9.10

Step-by-step explanation:

Jose paid $36.40 <em>in total </em> for 4 movie tickets.

Divide $36.40 with 4

36.40/4 = 9.1

$9.10 is the cost of one movie ticket.

~

7 0
3 years ago
X+y=c<br> x−y=a<br><br> solve for x and y
MrRissso [65]

Answer:

x = (c+a)/2

y = (c-a)/2

Step-by-step explanation:

Add the two equations and you get ...

(x +y) +(x -y) = (c) +(a)

2x = c+a

x = (c+a)/2

--

Subtract the second equation from the first and you get ...

(x +y) -(x -y) = (c) -(a)

2y = c-a

y = (c-a)/2

_____

Comment on this problem

This is what I call a "sum and difference" problem. The solution shown here is (obviously) the generic solution to such a problem. Remembering this can get you quickly to the answer any time you're given the sum of two unknowns and their difference.

7 0
4 years ago
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