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Licemer1 [7]
3 years ago
9

Find the cost of 1 1/2kg at 28p per kg

Mathematics
1 answer:
Norma-Jean [14]3 years ago
3 0
<u><em>Per KG:28</em></u>
<u><em>Total KG:</em>1<em>\frac{1}{2}×28=Y</em></u>
<u><em>Y=</em>1<em>\frac{1}{2}×28</em></u>
<u><em>Y=</em>1<em>.5×28=42</em></u>
<u><em>Y=</em>1<em>\frac{1}{2}×28=42</em></u>
<u><em>The total Cost is 42</em></u>
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a crew is setting up a zip line between two towers with support wires as shown in the figure (not to scale). they only know the
34kurt

Answer:

length of the zip line = 121. 63 ft

Step-by-step explanation:

The length of the zip line AB forms a triangle  ABC. To find the length AB we need to know the length of 2 sides of the triangle an angle.

Triangle ADC

We need to find the hypotenuse side AC using the SOHCAHTOA principle.

Therefore,

sin 41° = opposite/hypotenuse

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divide both sides by 0.65605902899

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AC = 99.0764506359  ft

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Triangle BCE

We are looking for side BC. The triangle BCE is also a right angle triangle so we use the same methodology like the triangle ADC.

sin 62° = opposite/hypotenuse

opposite = 85 ft

sin 62° = 85/BC

cross multiply

BC sin 62° = 85

BC = 85/sin 62°

BC = 85/0.88294759285

BC = 96.2684543086

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The angle ACB can be gotten when you subtract 62° and 41° from 180 (angle on a straight line).

Therefore,

∠ACB = 180° - 62° - 41°

∠ACB  = 77°

Now let us use the cosine law to find the zip line AB.

c² = a² + b² - 2ab cos C

a = 96.27 ft

b = 99.08 ft

c² = 96.27² + 99.08² - 2 × 96.27 × 99.08 cos 77°

c² = 9267.9129 + 9816.8464 - 19076.8632 cos 77°  

c² = 19084.7593 - 19076.8632 × 0.22495105434

c²  = 19084.7593 - 4291.36049041

c² = 14793.398810

square root both sides

c = √14793.398810

c = 121.628116856

c ≈ 121. 63 ft

length of the zip line = 121. 63 ft

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