Ask question

Ask question

All categories

Artyom0805 [142]

2 years ago

7

Maria is making a scale drawing of her basement, which is 12 yards long. if she let's 1/2 inch represent 1 yard how many inches

long should she make the drawing?
A.60
B.24
C.12
D.6

1 answer:

andrezito [222]2 years ago

7 0

Answer:

the correct answer would be 6 inches.

Step-by-step explanation:

12*.5=6

You might be interested in

Plz help!!!!! <br> ctc math

bija089 [108]

Answer:

7,13,37,55,103

Step-by-step explanation:

y = 5 + 2x^2

if x =1

y = 5 + 2(1)^2

1^2 = 1

2 x 1 = 2

y=5 + 2 or y = 7

you substatute each one in for x to solve for y

5 0

3 years ago

What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?

Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = $\frac{0.0625}{2}$ = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0

2 years ago

Read 2 more answers

Please help this is due in tommorow! I will mark you as brainliest!

pshichka [43]

Answer:

325.26

Step-by-step explanation:

that's the answer because you have to multiply the top

I have question do we have to do something to the bottom?

5 0

3 years ago

The abdominopelvic region that is bordered by all four imaginary lines is the

Ainat [17]

Umbilical point.

An umbilic point, likewise called just an umbilic, is a point on a surface at which the arch is the same toward any path.

In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

<span>Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.</span>

4 0

3 years ago

The table below represents the displacement of a turtle from its nest as a function of time: Time (hours) x Displacement from ne

andriy [413]

Part A: The y-intercept is 5. If you look to the data, when x=0, y=5. This means that the turtle started off 5 miles away from its nest. (at 0 hours, the distance away from his nest was 5 miles)

Part B:Answer=22. Remember, if you take any two distinct points on a line, the slope of the line will be equal to the average rate of change. In short, we're just looking for the slope between the ordered pairs (1,27) and (4,93). The formula for slope is:

$slope= \frac{y_{2}- y_{1} }{ x_{2} - x_{1} } = \frac{93-27}{4-1}= \frac{66}{3}=22$

The average rate of change between x=1 and x=4 is 22. The average rate of changed describes the rate at which miles is changing with respect the the change in hour.

Part C: Answer=10hours. Since by now we know both the slope and the y-intercept, lets write the equation in slope intercept form and then solve for 225 miles.

y=mx+b
y=22x+5
225=22x+5
subtract 5 from both sides
220=22x
divide both sides by 22
10=x
It would take 10 hours for the turtle to travel 225miles from it's nest.

4 0

3 years ago