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The trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ
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How to solve the trigonometric identity?</h3>
Since (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]
Using the identity a² - b² = (a + b)(a - b), we have
(cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]
= (cos²θ - sin²θ)(cos²θ + sin²θ)/[(1 - tan²θ)(1 + tan²θ)] =
= (cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] (since (cos²θ + sin²θ) = 1 and 1 + tan²θ = sec²θ)
Also, Using the identity a² - b² = (a + b)(a - b), we have
(cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] = (cosθ - sinθ)(cosθ + sinθ)/[(1 - tanθ)(1 + tanθ)sec²θ]
= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)/cosθ × (cosθ + sinθ)/cosθ × sec²θ]
= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)(cosθ + sinθ)/cos²θ × 1/cos²θ]
= (cosθ - sinθ)(cosθ + sinθ)cos⁴θ/[(cosθ - sinθ)(cosθ + sinθ)]
= 1 × cos⁴θ
= cos⁴θ
So, the trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ
Learn more about trigonometric identities here:
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Answer:
Graph G
Step-by-step explanation:
The graphs are attached
Given that the oil-well contractor drills a shaft 7 meters deeper into the ground every 2 hours, hence the rate at which the shaft drills = 7 meter / 2 hours = 3.5 meters per hour
Since the drill goes into the ground, hence the rate is negative that is -3.5 meters per secong
The slope (rate of change) of a line (m) is given by:

a) For graph F, the line passes through the point (0,0) and (10, -20). Hence:

b) For graph G, the line passes through the point (0,0) and (10, -70). Hence:

c) For graph H, the line passes through the point (0,0) and (10, -35). Hence:

d) For graph J, the line passes through the point (0,-3.5) and (10, -3.5). Hence:

hypotenuse (h) = 17 cm
using area of a triangle formula to solve for x
A =
bh ( b is the base and h the height )
× 5x(3x - 1 ) =60 ( multiply through by 2 )
5x(3x - 1)=120
15x² - 5x - 120 = 0 ← in standard form ( divide all terms by 5 )
3x² - x - 24 = 0
consider the factors of the product 3 × - 24 = - 72 which sum to - 1
The factors are - 9 and + 8 ( split the middle term using these factors )
3x² - 9x + 8x - 24 = 0 ( factor by grouping )
3x(x - 3) + 8(x - 3) = 0 ( take out common factor (x - 3) )
(x - 3 )(3x + 8) = 0 ( equate each factor to zero and solve for x )
x - 3 = 0 ⇒ x = 3
3x + 8 = 0 ⇒ x = - 
x > 0 ⇒ x = 3
the sides are 5x = 15 and 3x - 1 = 8
h = √(15² + 8² ) = √(225 + 64 ) = 17 ← ( hypotenuse )