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3 years ago

the area of a square ice rink is 404 square yards. To the nearest yard,what is the perimeter of the rink.

Mathematics

1 answer:

defon3 years ago

6 0

The perimeter of the square is 80 yards

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A building contractor is to dig a foundation 45 feet long, 16 feet wide and 6 feet deep. The contractor pays 13 dollars per load

9966 [12]

9514 1404 393

Answer:

160 yd³ must be hauled
$520 is the cost

Step-by-step explanation:

There are 3 feet in a yard, so the volume of the hole is ...

(45 ft)/(3 ft/yd) × (16 ft)/(3 ft/yd) × (6 ft)/(3 ft/yd)

= (15 × 16/3 × 2) yd³ = 160 yd³ . . . volume to be hauled

The cost is $13/(4 yd³), so the total cost will be ...

($13/(4 yd³)) × 160 yd³ = $520 . . . cost of hauling

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3 years ago

Ken buys two bunches of bananas. One bunch weighs 2 pounds 10 ounces. The other bunch weighs 1 pound 8 ounces. What is the total

nikklg [1K]

Answer:

4 pounds 2 oz

Step-by-step explanation:

16 oz = 1 pound so you add 10 and 8 to get 18-16 to get 4 pounds 2 oz

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3 years ago

Matthew’s math teacher gave him 6 tests. If his average was 72%, what was the sum of all of his tests? Show ALL of your work.

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I just took a guest and say 20

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3 years ago

Today only, a sofa is being sold at a 35% discount. The sale price is $559.

shusha [124]

Answer:

195.65

Step-by-step explanation:

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3 years ago

Read 2 more answers

Each of the faces of a fair six-sided number cube is numbered with one of the numbers 1 through 6, with a different number appea

makkiz [27]

Answer:

0.2

Step-by-step explanation:

If two number cubes as tossed then the total possible out comes are

Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

Number of elements in sample space are

n(S)=36

Let A and B represent the following events.

A = The sum will be 4.

A = {(1,3),(2,2),(3,1)}

n(A) = 3

B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

n(B)=15

Intersection of both events is

A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{36}$

$P(B)=\dfrac{n(B)}{n(S)}=\dfrac{15}{36}$

$P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{3}{36}$

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

$P(\frac{A}{B})=\dfrac{P(A\cap B)}{P(B)}$

$P(\frac{A}{B})=\dfrac{\frac{3}{36}}{\frac{15}{36}}$

$P(\frac{A}{B})=\dfrac{3}{15}$

$P(\frac{A}{B})=\dfrac{1}{5}$

$P(\frac{A}{B})=0.2$

Therefore, the required probability is 0.2.

3 0

3 years ago