Question

Worth 45 points. Solve. 4k^2+12k+8

Answer 1

Answer:

k = -1, -2.

Step-by-step explanation:

4k^2+12k+8 = 0

Divide by 4:

4(k^2 + 3x + 2) = 0

4(k + 1)(k + 2) = 0

k = -1, -2.

Answer 2

Answer:

k = -1 and k = -2

Step-by-step explanation:

We can use the quadratic formula, which says that for the quadratic $ax^2+bx+c=0$, the solutions are: x = $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$ .

Here, a = 4, b = 12, and c = 8, so: x = $\frac{-12+\sqrt{12^2-4*4*8} }{2*4}$ or $\frac{-12-\sqrt{12^2-4*4*8} }{2*4}$.

Simplifying, we get k = -1 or k = -2.

Thus, k = -1 and -2.

Hope this helps!