Here are some important points:
- we use it to do essays for school
- we can use it to do flyers for recreational events
- we can use it to do pamphlets to inform people
- it is versatile, so you can create many different types of documents
- you can create charts
This can be your opening statement
Today, there is a lot asked of a child in school. From charts to essay to projects, the average kid has at least 10 different programs they use just for one project. But there is one program that came along and changed everything, and that program is called Microsoft word. Microsoft word is valuable because it is versatile (what I wrote earlier about it being able to do many different tasks), it simplifies your experience (what i said about it being able to combine different programs into one), and it is free (you can write about how some programs charge to use their high-grade programs but microsoft is free and avaialabe on every windows
computer.)
GOOD LUCK !
Answer:
Explanation:
The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a number of type double to calculate square root:");
double num = in.nextDouble();
rootPositive(num);
}
public static void rootPositive(double num) {
if (num > 0) {
System.out.println(Math.sqrt(num));
} else {
System.out.println("Number must not be negative.");
}
}
}
Answer:
b.used is 2, b.data[0] is 4, b.data[1] is 6
Explanation:
bag b;
b.insert(5); // b has 5
b.insert(4); // b has 5,4
b.insert(6); // b has 5,4,6
b.erase_one(5); // now 5 is removed , b has 4,6
so no:of elements b.used is 2
b[0]=4;
b[1]=6;
Answer:
Number of strings = (10, 2)×(8,3) = 2520
Explanation:
The number of possible combinations for taking two 0's is C(10, 2)
It remains 8 Positions
The number of possible combinations for taking three 1's is C(8,3)
So there remains 5 spots
