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Serhud [2]
4 years ago
11

Evaluate the expression 1/3 (4+18) 4

Mathematics
1 answer:
MArishka [77]4 years ago
5 0

Answer:

29 1/3

Step-by-step explanation:

1/3 (4 + 18) 4

1/3 (22) 4

7 1/3 x 4

29 1/3

Twenty nine and one third is your answer.

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Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.
umka21 [38]
Complex zeroes always occurs as conjugates.
For z = a + b i conjugate is: a - b i
Another zero is : 2 + 3 i.
Verification:
2 + 3 i + 3 - 3 i = - b/a
- b = 4,  a = 1
( 2 + 3 i ) ( 2 - 3 i ) = c / a
4 - 9 i² = c / a
4 + 9 = c / a
c = 13
( x^4 - 4 x³ + 14 x² - 4 x + 13 ) : ( x² - 4 x + 13 ) = x² + 1
x² + 1 = 0
x² = -1,  x = i,  x = -i
The zeroes are: - i , i , 2 + 3 i, 2 - 3 i.
Answer: 
One another zero of f ( x ) is 2 + 3 i.
7 0
4 years ago
Please help me I need to pass
Liula [17]
Any value less than 16 or greater than 24 is an outlier.

This is because 16 is the smallest number in the data and 24 is the largest, any more different than this makes a number an outlier
4 0
3 years ago
Given that AB parallels QR, AB bisects AE, QR bisects QT
enyata [817]

Answer:

  1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

  2. Translate A' to Q

Step-by-step explanation:

We notice the triangles have the same orientation, so no reflection or rotation is involved. The desired mapping can be accomplished by dilation and translation:

  1. Dilate ΔABE by a factor of 2/5 to make ΔA'B'E'

  2. Translate A' to Q

The result will be that ΔA"B"E" will lie on top of ΔQRT, as required.

5 0
3 years ago
Eliminate the parameter. x = t^2 + 1, y = t^2 - 1.
Maksim231197 [3]

Answer:

Eliminating the parameter, the equation is y = x - 2

Step-by-step explanation:

We are given the following parametric equations:

x = t^2 + 1

y = t^2 - 1

We want to eliminate the parameter t. From the first equation:

x = t^2 + 1

t^2 = x - 1

Replacing in the second equation:

y = x - 1 - 1

y = x - 2

Eliminating the parameter, the equation is y = x - 2

7 0
3 years ago
The vertex of the parabola below is at the point (-4,-2) wich of the equations below could be the one for this parabola
MrRissso [65]

The parabola with with a vertex at (-4,-2) represents any member of parabolas with the equation y(x)=a(x+4)^2-2 where a is any real number with the exception that  a\neq 0.

The reason any equation  of the form y(x)=a(x+4)^2-2 works is that there are an infinite number of parabolas with a vertex at (-4,-2). All of these parabolas are formed by applying some transformation that involves a vertical translation of -2 and a horizontal translation of -4 on the parabola y=x^2. The different variations are archived by varying the constant a.  When a is negative, the parabolas will face downwards. When a is negative, the parabolas will be face downwards.

6 0
3 years ago
Read 2 more answers
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