All categories

3 years ago

What is the slope of any line parallel to the line 4x + 3y = 9?

Mathematics

1 answer:

TiliK225 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

4x + 3y = 9 ⇔ 3y = 9 - 4x ⇔ y = -4/3x + 3 then the slope of our line is -4/3

Then any line parallel to the line 4x + 3y = 9 must have a slope of -4/3.

You might be interested in

Simplify the expression where possible.<br><br> (-5x2)^3

Paul [167]

Answer:

-1000

Step-by-step explanation:

1. Do the Parenthesis problem first. (PEDMAS/PEMDAS)

You should then have -10^3

2. Solve with the exponent. (-10 x 10 x 10)

You should then get your final answer, which is -1000.

Any Questions/Concerns?

6 0

3 years ago

Convert 13/25 to a decimal

sergejj [24]

The decimal form is 0.52

3 0

3 years ago

Solve -8/5 x - 6 = -54

Musya8 [376]

The equation is false so no solution.

Simplify 8/5 * -6 to -48/5

Move the negative sign to the left

Simplify brackets

Since 48/5 = -54 its false so no answer

4 0

3 years ago

Read 2 more answers

How do you know when a sequence is arithmetic vs. geometric?

stellarik [79]

Answer:

An arithmetic sequence is a sequence with the difference or pattern between two consecutive terms constant.

A geometric sequence is a sequence with a ratio between two consecutive terms constant.

8 0

3 years ago

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

kirill115 [55]

Answer:

The Correct option is Last one $y=-4x-4$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

Step-by-step explanation:

Given:

$y=-4x-3$

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

$y=-4x-3$ ..........Given

Comparing with Slope-Intercept form,

$y=mx+c$

Where m =slope

We get

$Slope = m = -4$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

8 0

3 years ago