Let z be any number (like x would be)
if we set z equal to 2x-6y, then we get z = 2x-6y
The system
2x-6y = 8
2x-6 = 3
turns into this new system
z = 8
z = 3
but z is a single number. It can't be both 8 and 3 at the same time. So there are no solutions
Answer: r=7x-1/8
Step-by-step explanation:
2(4r+3)=7x/2+5/2
4r+3=7x+5/2
4r+3-3=7x+5/2 -3
4r=7x+5/2 -3
4r/4= 7x-5/2/4 -3/4
r=7x-1/8
Answer:
$1800
Step-by-step explanation:
1. Approanch
An easy way to calculate one's salary after they recive a raise is to, convert the percent that one's salary is increased into a decimal; divide the percent by 100. Then multiply the increase as a decimal by the original salary, to attain the amount the salary is raised by. Finally add the amount the salary is raised by to the original salary to find the new salary. A quicker way to do this is to convert the percent by the salary is increased into a decimal. Then add 1 to that number. Finally one will multiply that number by the original slary and get the new salary.
2. Solving
Original salary; 1500
Raise; 20%
<u>a. convert the raise as a percent into a decimal, then add 1</u>
20% = 0.2
0.2 + 1 = 1.2
<u>b. multiply the number by the original salary</u>
1.2 * 1500
1800
Answer:
It is irrational and equal to 5 times the square root of 2.
Step-by-step explanation:
The statement that is true about the expression:
( √(32) ) + √2
( √(16 * 2) ) + √2
( √(4²) *√2 ) + √2
( 4 *√2 ) + √2
( √2+√2+√2+√2 ) + √2
...and this is ( 4 ) + 1 times √2
The answer is 5 times √2
So the expression is irrational and equal to 5 times the square root of 2.
Given the following function:
![\text{ f(x) = }\sqrt[]{-x\text{ -2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x%5Ctext%7B%20-2%7D%7D%5Ctext%7B%20%2B%202%7D)
y = f(x)
Therefore, let's complete the data table by substituting each x-values to be able to get the respective y-values,
We get,
At x = -2,
![\text{ y = f(x) = }\sqrt[]{-x-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20y%20%3D%20f%28x%29%20%3D%20%7D%5Csqrt%5B%5D%7B-x-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{f(-2) = }\sqrt[]{-(-2)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-2%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-2%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{2\text{ - 2}}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B2%5Ctext%7B%20-%202%7D%7D%5Ctext%7B%20%2B%202%7D)
![\text{ = }\sqrt[]{0}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B0%7D%5Ctext%7B%20%2B%202%7D)
Therefore, y = 2 at x = -2.
At x = -3,
![\text{f(-3) = }\sqrt[]{-(-3)-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7Bf%28-3%29%20%3D%20%7D%5Csqrt%5B%5D%7B-%28-3%29-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{3-2}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B3-2%7D%5Ctext%7B%20%2B%202%7D)
![\text{= }\sqrt[]{1}\text{ + 2}](https://tex.z-dn.net/?f=%5Ctext%7B%3D%20%7D%5Csqrt%5B%5D%7B1%7D%5Ctext%7B%20%2B%202%7D)
Therefore, y = 3 at x = -3.
At x = -6,
