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katrin2010 [14]
3 years ago
15

WILL GIVE BRAINLIEST ASAP, EASY 8TH GRADE MATH, MORE THAN 5 POINTS! The formula for the circumference of a circle is: c = 2πr So

lve for the radius, r, by dividing both sides by 2π. What is the formula for the radius of a circle in terms of the circumference? r = 2 pi c or r = c / 2 pi or r = pi / 2 c or r = 2 pi / c
Mathematics
2 answers:
solmaris [256]3 years ago
4 0

Answer:

c/2(Pi)=r

Step-by-step explanation:

Divide both sides by 2(pi)

Brilliant_brown [7]3 years ago
3 0

Answer:

r = \frac{C}{2\pi }

Step-by-step explanation:

We simply are rearranging C= 2πr in terms of <em>r</em>. We just divide 2π on both sides.

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Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

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c.

Class boundaries

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Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

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