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Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer: 4,280
Step-by-step explanation:
Hi
<span>i=prt
where i is interest (9000-6000 = $3000 interest)
p is principle ($6000)
r is rate (5.5%) [taking that its 5.5%pa]
t is time
substitute these into the equation
3000 = $6000 x 5.5% x t
t = 3000 divided by (6000x5.5%)
= 3000 divided by 330
t=100/11 years
it would take 100/11 years which is approx 9.1 years</span>
Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.
- sinA = opposite/hypotenuse
- cosA = adjacent/hypotenuse
- tanA = opposite/adjacent
Now that we know three basic ratio. Let's check each choices!
This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.
This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.
This choice is correct! As ratio states, tanA = opposite/adjacent.
This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.
This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.
This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.
Answer
Questions can be asked through comment.
Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.
Hope this helps, and Happy Learning! :)
