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3 years ago

Can I please get help with this I give thanks

Mathematics

2 answers:

gladu [14]3 years ago

6 0

First one :
We divide it into two rectangles (the top one has dimensions 2in*4in)

The area of the top rectangle is 2*4=8 in^2

The second rectangle has dimensions 3*(5-3)=6 in^2
Hence the total area is 8+6=14 square inches

Second one :
We divide it into a rectangle (dimensions 11*17) and a triangle on the top.

The area of the rectangle is 11*17=187 m^2
The rectangle has dimensions 17 (base's length) and 23-11 (height) hence its area is 17*(23-11)/2=102 m^2

Hence the total area is 102+187=289 square meters

777dan777 [17]3 years ago

5 0

For the first shape split the 'L' into two rectangles; one with a length of 5 inches and a height of 3 inches, we'll call is shape J, the other with a height of 4 inches and a length of 2 inches, this one can be called shape K. (I've basically drawn an imaginary line across the middle). It's a lot easier to work out area this way, simple height multiplied by length. J = 5 x 3 = 15 inches. K = 4 x 2 = 8 inches. Add the two together and you get the area of the whole shape: 23 square inches. *It's important to remember units.* I don't know for sure how to do the second shape (sorry) but I was asked to help out with this question, so I did. I suggest you split the shape again, but this time into a triangle and a rectangle which is far easier to calculate and area for.

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An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours

Firdavs [7]

Answer

Find out the which system of equations could be used to determine the number of hours charged at the day rate (d) and at the night rate (n) .

To proof

As given in the question

Let us assume that the number of hours charged at the day rate = d

Let us assume that the number of hours charged at the night rate = n

An online data base charges $25 an hour during the day and $12.50 an hour at night. If a research company paid $250 for 12 hours of use.

Total working hour in a company including day and night be 12 hours .

than the equation become in the form

d + n = 12

also

An online data base charges $25 an hour during the day

$12.50 an hour at night.

If a research company paid $250 for 12 hours of use.

than the equation becomes

25d + 12.50n = 250

than the two equation are

d + n = 12 , 25d + 12.50n = 250

multiply first by 25 and subtracted from 25d + 12.50n = 250

25d - 25d + 12.50n - 25n = 250 - 300

12.5 n = 50

$n = \frac{50}{12.5}$

n = 4hours

put this in the d + n = 12

d + 4 =12

d = 12-4

d = 8 hours

Therefore the number of hours charged at the day rate is 8 hours and at the night rate is 4hours .

Hence proved

4 0

4 years ago

What’s the value of x? :/

kolbaska11 [484]

Answer:

$x = 27$

Step-by-step explanation:

According to congruent chords and arcs theorem, if $\overline{XY} \cong \overline{ZY}$ then $\arc{XY} \cong \arc{ZY}$ .

This means that $\arc{XY} = \arc{ZY} = (6x - 20) degrees$

Thus:

$\arc{XY} + \arc{ZY} + \arc{ZX} = 360$ (full circle = 360°)

$\arc{XY} = (6x - 20)$

$\arc{ZY} = (6x - 20)$

$\arc{ZX} = 76$

Plug in the values into the equation

$(6x - 20) + (6x - 20) + 76 = 360$

$6x - 20 + 6x - 20 + 76 = 360$

Add like terms

$12x + 36 = 360$

Subtract 36 on both sides

$12x = 360 - 36$

$12x = 324$

Divide both sides by 12

$x = 27$

8 0

3 years ago

URGENT HELP PLEASE.

AlladinOne [14]

W + 2w = 60

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6 0

4 years ago

Workers have been down the street installing two blinking red lights in front of the fire station. The two lights are always tur

daser333 [38]

Answer:

After 88 seconds, they will blink together.

Step-by-step explanation:

Time after which the first light blinks = 8 seconds

Time after which the second light blinks = 22 seconds

Initially, both the lights blink together.

To find:

The time at which they will blink together again.

Solution:

Let us have a look at the time after which each light will blink.

First light will blink after:

8 s, 16 s, 24 s, 32 s, 40 s, 48 s, 56 s, 64 s, 72 s, 80 s, 88 s, 96 s, 104 s, ......

Second light will blink after:

22 s, 44 s, 66 s, 88 s, 110 s, .....

It can be seen that common time is 88 second, at which the both will blink together.

So, the answer is 88 s.

This answer can also be computed by taking the LCM (Least Common Multiple) of both the numbers i.e. 8 and 22.

Using the factorization method:

$8=\underline{2}\times 2\times 2$

$22=\underline{2}\times 11$

Common is 2.

Therefore the LCM will be:

$2\times 2\times2\times 11 = \bold{88}$

So, the answer is 88 s.

5 0

3 years ago

PLEASE HELP WITH THIS MATHS QUESTION thank you :D

trasher [3.6K]

A)106°- angle at the centre is half of the angle at the circumference

b)74°- when a tangent meets a radius a right angle is created(90+90+106)= 286 360-286= 74°

4 0

4 years ago