It’s should be 30 if the triangle is drawn to scale

It would absolutely not be 180 because that’s the sum of all angles of the triangle

It could be 75 but if the triangle is drawn to scale then the two isosceles angle should be greater than angle U, so it won’t be reasonable if angle U is 75

8 0

3 years ago

Find the value of the following expression: (2^8 • 3^-5 • 6^0)^-2 • (3^-2 over 2^3)^4 • 2^28 write your answer in simplified for

user100 [1]

Put it in the calculator

7 0

3 years ago

A random sample of 30 males with online dating profiles are recruited for a study about lying in online dating profiles. Each ma

laiz [17]

Answer:

The 95% confidence interval for the difference in mean profile height and mean actual height of online daters is between 0.27 and 0.87 inches.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 30 - 1 = 29

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 29 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0452

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.0452\frac{0.81}{\sqrt{30}} = 0.3$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 0.57 - 0.3 = 0.27 inches.

The upper end of the interval is the sample mean added to M. So it is 0.57 + 0.3 = 0.87 inches.

The 95% confidence interval for the difference in mean profile height and mean actual height of online daters is between 0.27 and 0.87 inches.

3 0

2 years ago