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Dmitry [639]
3 years ago
9

Anlatarak cevaplarsanız sevinirim

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

A)26

Step-by-step explanation:

12 nin dogal sayi bolenleri 1,2,3,4,6 ve 12 dir yani ucgen 6 dir

20 nin en kucuk kati 20 yani kendisidir(20 kendisinin 1 katidir)

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Get Big Brain for this!!!
laiz [17]

Answer:

That would be impossible because you would get melted by the earth core

Step-by-step explanation:

7 0
3 years ago
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Find an equation of the plane. The plane that passes through the line of intersection of the planes x − z = 3 and y + 4z = 1 and
Nata [24]

Answer:

• 3x +y +z = 10

Step-by-step explanation:

The cross product of the normals of the intersecting planes will give a vector that is parallel to the line of intersection.

(1, 0 -1) × (0, 1, 4) = (1, -4, 1) . . . . using an appropriate calculator

Since this line is in the desired plane, it will be perpendicular to the desired plane's normal vector. The reference perpendicular plane likewise has its normal vector perpendicular to that of the desired plane. Hence the normal vector of the desired plane is perpendicular to both (1, -4, 1) and (1, 1, -4). It can be found from the cross product of these:

(1, -4, 1) × (1, 1, -4) = (15, 5, 5)

We can divide this by 5 to find our desired plane's normal vector: (3, 1, 1). To finish the equation of our plane, we need to know a point on the line of intersection. If we suppose z=0 at that point, then the remaining coordinates are ...

x -0 = 3 ⇒ x=3

y+4·0 = 1 ⇒ y=1

Using point (3, 1, 0) to find the constant in our plane's formula

3x +y +z = constant

we see it is ...

3·3 +1·1 +1·0 = constant = 10

The equation of the desired plane is ...

3x +y +z = 10

3 0
4 years ago
Line segment XY is located at X(2, 6) and Y(4,8). If the line segments is dilated by a scale factor of 2 with a center of dilati
Kamila [148]

Given:

Line segment XY is located at X(2, 6) and Y(4,8).

The line segments is dilated by a scale factor of 2 with a center of dilation of T(-3, 4).

To find:

The coordinates of X'

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If a figure dilated by a scale factor k with a center of dilation (a,b), then the rule of dilation is:

(x,y)\to (k(x-a)+a,k(y-b)+b)

The line segments is dilated by a scale factor of 2 with a center of dilation of T(-3, 4). So, the rule of dilation is

(x,y)\to (2(x-(-3))+(-3),2(y-4)+4)

(x,y)\to (2(x+3)-3,2y+2(-4)+4)

(x,y)\to (2x+6-3,2y-8+4)

(x,y)\to (2x+3,2y-4)

The coordinate of X are (2,6).

X(2,6)\to X'(2(2)+3,2(6)-4)

X(2,6)\to X'(4+3,12-4)

X(2,6)\to X'(7,8)

Therefore, the coordinates of X' are (7,8).

7 0
3 years ago
Is (-8, -10) a solution to this system of equations?
Dmitrij [34]

Answer:

No is something worng

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

I graphed the equation on the graph below to find the vertex of the equation.

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