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Stells [14]
3 years ago
11

I just want someone to check if i did all these correctly according to the directions

Mathematics
1 answer:
tekilochka [14]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

For number 3 you answered them all correctly as well as number 4 and 5. Don't hesitate asking questions like these :D

You might be interested in
Factor completely 15x^5 + 12x^4-24x^3-3x^2
diamong [38]

Answer:

3x^2 (5x^3 + 4x^2 - 8x - 1)

Step-by-step explanation:

The given expression is 15x^5 + 12x^4-24x^3-3x^2

Here we have to find the GCF of all the above terms.

The GCF is 3x^2, let's take out 3x^2 and write the remaining terms in the parenthesis.

15x^5 + 12x^4-24x^3-3x^2

=3x^2 (5x^3 + 4x^2 - 8x - 1)

Therefore, the factors are 3x^2 and (5x^3 + 4x^2 -8x -1).

15x^5 + 12x^4-24x^3-3x^2 = 3x^2 (5x^3 + 4x^2 -8x -1)

Thank you.

7 0
3 years ago
During the final 5 seconds of a race a cyclist increased her velocity from 4 m/s to 7 m/s . What was her average acceleration du
GREYUIT [131]

Answer:

The average acceleration of the cyclist was 0.6 m/s².

Step-by-step explanation:

Acceleration:

The rate change of velocity per unit time is call the acceleration of the object.

a=\frac{v-u}t

u= initial velocity

v= final velocity

t= time taken change of velocity.

During the final 5 seconds of a race cyclist increased her velocity from 4m/s to 7 m/s

Here v= 7 m/s and u=4 m/s t=5 seconds

\therefore a=\frac{7\ m/s-4 \ m/s}{5s}

     =\frac{3}{5} \ m/s^2

     =0.6 m/s²

The average acceleration of the cyclist was 0.6 m/s².

8 0
3 years ago
What is the gcf of 23 and 50
valkas [14]

Answer:

The greatest common factor of 23 and 50 is 1

Step-by-step explanation:

7 0
3 years ago
Question: The meaning of four consecutive even numbers is 15.
nasty-shy [4]
First, a bit of housekeeping:

<span>The meaning of four consecutive even numbers is 15.  Wouldn't that be "mean," not meaning?  Very different concepts!

The greatest of these numbers is _______ a^1

"a^1" means "a to the first power.  There are no powers in this problem statement.  Perhaps you meant just "a" or "a_1" or a(1).


The least of these numbers is ______a^2.
No powers in this problem statement.  Perhaps you meant a_2 or a(2)


In this problem you have four numbers.  All are even, and there's a spacing of 2 units between each pair of numbers (consecutive even).

The mean, or arithmetic average, of these numbers is (a+b+c+d) / 4, where a, b, c and d represent the four consecutive even numbers.  Here this mean is 15.  The mean is most likely positioned between b anc c.


So here's what we have:  a+b+c+d
                                         ------------- = 15
                                                 4

This is equivalent to a+b+c+d = 60.

Since the numbers a, b, c and d are consecutive even integers, let's try this:

a + (a+2) + (a+4) + (a+6) = 60.    Then 4a+2+4+6=60, or 4a = 48, or a=12.

Then a=12, b=14, c=16 and d=18.  Note how (12+14+16+18) / 4 = 15, which is the given mean.

We could also type, "a(1)=12, a(2)=14, a(3) = 16, and a(4) = 18.


</span>
8 0
3 years ago
Solve x3 = 64 over 27.
const2013 [10]

x^3 = 64/27

x^3 = (4*4*4)/(3*3*3)

x^3 = (4/3)^3

x = 4/3

ans is d


5 0
3 years ago
Read 2 more answers
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