The answer is; opioids
These painkillers relieve pain by competing with neurotransmitters in binding neurotransmitter receptors in the synapse. However, they don’t induce an impulse hence block the receptors from neurotransmitters. This working principle, however, is also problematic because it causes slow breathing because the drugs calm nerve activity even that which controls your breathing.
The genetic fault that usually causes colour vision deficiency is passed on in what's known as an X-linked inheritance pattern.
This means:
1) it mainly affects boys, but can affect girls in some cases
2) girls are usually carriers of the genetic fault – this means they can pass it on to their children, but do not have a colour vision deficiency themselves
3) it's usually passed on by a mother to her son – the mother will often be unaffected as she'll normally just be a carrier of the genetic fault
4) fathers with a colour vision deficiency will not have children with the problem unless their partner is a carrier of the genetic fault
5) it can often skip a generation – for example, it may affect a grandfather and their grandson
6) girls are only affected if their father has a colour vision deficiency and their mother is a carrier of the genetic fault
No this is for extra words
Answer:
- 1/2 = 50% de la progenie será roja heterocigota, Rr
- 1/2 = 50% de la progenie será blanca homocigota recesiva, rr.
Explanation:
- El gen que codifica para el color de flor es dialélico
- El alelo R es dominante y expresa color rojo en homocigosis y heterocigosis.
- El alelo r es recesivo y expresa el color blanco en homocigosis.
Cruza: flores rojas heterocigotas con flores blancas
Parentales) Rr x rr
Fenotipo) Rojo Blanco
Gametas) R r r r
Cuadro de Punnett)
R r
r Rr rr
r Rr rr
F1) 2/4 = 1/2 = 50% de la progenie será roja heterocigota, Rr
2/4 = 1/2 = 50% de la progenie será blanca, rr.
The question is incomplete, the complete question is;
complete the half reactions for the cell shown here and show the shorthand notation for the cell by dragging labels to the correct position. The electrode on the left is the anode, and the one on the right is the cathode.
in the left side there is a solution of Pbcl2(s) and it contains the elctrode pb and on the right side there is solution of AgCl(S) which contains the electrode Ag. There is inverted glass tube with Kcl (aq) on the left and and Kcl(aq) on the right.
Anode half-reaction:
Blank + 2Cl^- equilibrium arrow yields Blank + 2e^-
Cathode half reaction:
Blank +2e^- equlibriums arrow yields Blank + 2Cl^-
Shorthand notation: Please provide.
Answer:
Explanation:
Let us remember that oxidation occurs at the anode while reduction occurs at the cathode. This will guide our work here. The Pb(s)/Pb^2+(aq) is the anode while the Ag^+(aq)/Ag(s) is the cathode
Anode half-reaction:
Pb(s) + 2Cl^- ⇄ Pb^2+(aq) + 2e^-
Cathode half reaction:
2Ag^+(aq) + 2e^- ⇄ 2Ag(s) + 2Cl^-
Overall reaction equation;
Pb(s) + 2Ag^+(aq) ⇄ Pb^2+(aq) + 2Ag(s)
Shorthand notation;
Pb(s)/Pb^2+(aq)//Ag^+(aq)/Ag(s)