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WARRIOR [948]
3 years ago
6

Yesterday's World Cup final had viewing figures of 138,695,157. What is the value of the 3?

Mathematics
1 answer:
crimeas [40]3 years ago
8 0

Answer:

The value of the 3 is 30,000,000.

Step-by-step explanation:

From the digit at the right, you go multiplying each element by 10 powered to a counter that starts at zero and increases at every digit. So:

Our counter is i

i = 0;

v(7) is the value of the 7

v(7) = 7*10^{0} = 7

i = 1;

v(5) is the value of the 5

v(5) = 5*10^{1} = 50

i = 2;

v(1) is the value of the 1

v(1) = 1*10^{2} = 100

i = 3;

v(5) is the value of the 5

v(5) = 5*10^{3} = 5,000

i = 4;

v(9) is the value of the 9

v(9) = 9*10^{4} = 90,000

i = 5;

v(6) is the value of the 6

v(6) = 6*10^{5} = 600,000

i = 6;

v(8) is the value of the 8

v(8) = 8*10^{6} = 8,000,000

i = 7;

v(3) is the value of the 3

v(3) = 3*10^{7} = 30,000,000

The value of the 3 is 30,000,000.

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How many times does 12 go into 95
JulsSmile [24]

Answer:7

Step-by-step explanation:

95/12=7.916666666666666666666666666

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3 years ago
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Joan and her brother Justin left a hotel at the same time, driving in opposite directions at constant rates. After traveling for
inessss [21]

Answer:

Joan drive with a speed of 55 miles per hour.

Step-by-step explanation:

Given:- Travelling time (t) = 4 hours.

Travelled distance (d) = 480 miles.

Speed of Justin is 10 miles per hour faster than Joan.

To find:- Speed of Joan = ?

Solution:-

Let speed of Joan be x,

therefore speed of Justin = x+10          ---------------(from given)

Now, Total speed of Joan and Justin = x+x+10

Total speed of Joan and Justin = 2x+10 ------------(1)

Now formula for speed is,

Speed = \frac{distance}{time}

2x+10=\frac{480}{4}                        -------------(from 1 and given)

2x+10=120

2x=120-10

2x=110

\therefore x=\frac{110}{2}

\therefore x= 55

as x is the speed of Joan,

Therefore Joan drive with a speed of 55 miles per hour.

6 0
3 years ago
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Forty-seven percent of fish in a river are catfish. Imagine scooping out a simple random sample of 25 fish from the river and ob
Romashka-Z-Leto [24]

Answer: The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 fish in the river.

Step-by-step explanation:

The standard deviation of the sampling distribution = \sqrt{\dfrac{p(1-p)}{n}} , where p= population proportion and n = sample size.

Let p be the proportion of  fish in a river are catfish.

As per given , we have

p= 0.47

n= 25

The, the standard deviation of the sampling distribution will be \sqrt{\dfrac{0.47(1-0.47)}{25}}

=\sqrt{0.009964}\approx0.0998

The 10% condition : Sample sizes should be no more than 10% of the population.

But a river can have more than 250 fish [where 10% of 250 =25 (sample size)]

i.e. The 10% condition is met because it is very likely there are more than 250 fish in the river.

So the correct answer is "The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 fish in the river."

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3 years ago
Solve system by elimination <br> -9x+7y=22<br> 9x-5y=-26
alisha [4.7K]

Answer:

The solution would be (-4, -2)

Step-by-step explanation:

To find this simply add the two equations together.

-9x+7y=22

9x-5y=-26

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2y = -4

y = -2

Now we have the y value, we can solve for the x value.

9x-5y=-26

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3 years ago
Part 2: Use the information provided to write the standard form equation of each circle
Archy [21]

Answer:

The answer to your question is below

Step-by-step explanation:

- The Standard form of the equation is

                  (x - h)² + (y - k)² = r²

4.

Center (8, -4)    r = \sqrt{118}

-Substitution

                 (x - 8)² + (y + 4)² =\sqrt{118}²                

-Result

                 (x - 8)² + (y + 4)² = 118

5.

Center (-10, 9)     r = \sqrt{37}

-Substitution

                  (x + 10)² + (y - 9)² = \sqrt{37}²                

-Result

                  (x + 10)² + (y - 9)² = 37

6.-

Center (-8, 0)       r = 6

-Substitution

                  (x + 8)² + (y - 0)² = (6)²

-Result

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