The arc is equal to the half of circumference.
The formula for circumference is
. Now divide that by 2 and you get ![69.11\div2\approx\boxed{34.56}](https://tex.z-dn.net/?f=69.11%5Cdiv2%5Capprox%5Cboxed%7B34.56%7D)
Semicircular arc has a length of approximately 34.56
Hope this helps.
r3t40
Answer:
The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.
Step-by-step explanation:
Given,
CGPA = 2.75
Credit hours = 105
Last semester GPA = 4
Last semester credit hours = 15
CGPA =
credit hours * gpa
in our case, it would be:
CGPA = ![\frac{(2.75*105)+(4*15}{105+15}](https://tex.z-dn.net/?f=%5Cfrac%7B%282.75%2A105%29%2B%284%2A15%7D%7B105%2B15%7D)
=> ![\frac{(288.75)+(60)}{120}](https://tex.z-dn.net/?f=%5Cfrac%7B%28288.75%29%2B%2860%29%7D%7B120%7D)
=> ![\frac{348.75}{120}](https://tex.z-dn.net/?f=%5Cfrac%7B348.75%7D%7B120%7D)
=> 2.90
The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.
3. A.-2
4. B.2
Hope this helps
Answer:
Pete: 39, Linda: 42
Step-by-step explanation:
Suppose Pete has x dollars. If he has 3 dollars less than Linda, then Linda has 3+x dollars. Together, they have 81 dollars:
x+3+x=81
2x+3=81
2x=78
x=39
Since Pete has x dollars, and x=39, he has $39.
Linda has 3+x, which is 39+3 = $42
<em>I hope this helps! :)</em>