Answer:
Option B. y = 2x; 20 feet
Step-by-step explanation:
1. Determination of the equation that represents the relationship.
Let y be the distance travelled.
Let x be the time taken.
Let K be the speed.
From the question given above, the following data were obtained:
Distance (y) = 80 ft
Time (x) = 40 s
Speed (k) =.?
Speed = Distance /time
K = y/x ......... (1)
K = 80/40
K = 2 ft/s
Substitute the value of k into equation 1
K = y/x
K = 2 ft/s
2 = y/x
Cross multiply
y = 2x
Therefore, the equation that represents the relationship is y = 2x
2. Determination of the distance travelled in 10 s.
Speed (k) = 2 ft/s
Time (x) = 10 s
Distance (y) =.?
y = 2x
y = 2 × 10
y = 20 ft
Therefore, the person will travel 20 feet in 10 seconds.
From the above calculations, the right answer to the question is
Option B. y = 2x; 20 feet
Answer: I believe the first one is ASA, and the third one is SAS, however for the second one, I think it’s none or ASA
Answer:
t5hfji8uor/y(7.08) = 75fovuobb
Step-by-step explanation:
hope this helps
Answer:
The first expression can be rewritten as
35 {b}^{2} = 5 \times 7 \times {b}^{2}35b
2
=5×7×b
2
The second expression is rewritten as
15 {b}^{3} = 3 \times 5 {b}^{3}15b
3
=3×5b
3
The third expression is
5b = 5 \times b5b=5×b
The greatest common factor is the product of the least powers of the common factors.
