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mihalych1998 [28]

3 years ago

8

There are 30 students in Mr.Thomas' class.If he wants 20% of the students in each group, how many students will be in. each grou

p?

2 answers:

zhuklara [117]3 years ago

8 0

First you find out what 20% of 30 is (30 * 0.20 = 6)
Then you take 30/6 to get your answer (30/6 = 5)
There will be 5 students in each group.

ANTONII [103]3 years ago

4 0

I believe that there would be 5 students in each group

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Marshall left home biking at a constant rate of 20 mph. One hour later, it looked like it may rain, so his friend, Brett, set ou

xxTIMURxx [149]

Answer:

First, we need to find how far ahead Marshall was. Since he had been biking at 20 mph for one hour, he had gone 20 miles.

Next, we need to find how long it will take Brett to catch up to Marshall. In order to do this, we need to find how much faster Brett is going than Marshall. We do this by subtracting Marshall's speed from Brett's speed.

60 - 20 = 40. So, Brett is catching up to Marshall at 40 mph. Now, we figure out how long it will take for someone going 40 miles per hour to go 20 miles. We find this by dividing 40 miles per hour by 20. This is equal to 1/2 hour. So, it will take Brett 0.5 hours to catch up to Marshall. This is the same as A, so A is the correct answer.

We can check our answer by seeing how far Marshall and Brett will have gone. Marshall will have been biking for 1.5 hours, so we multiply 20 * 1.5 = 30. Marshall went 30 miles.

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4 0

3 years ago

Round to the thousandth place: 82.6925

Vinvika [58]

82.693

the rule is when its 4 and under round down and 5 and up round up

4 0

3 years ago

200 students study either Geography or History.

romanna [79]

Answer:

i think you forgot the table

Step-by-step explanation:

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4 0

3 years ago

(4x-y=-15)<br>(3x-2y=-10)<br>

Andreyy89

Answer:

<h2>x = -4 and y = -1 → (-4, -1)</h2>

Step-by-step explanation:

$\left\{\begin{array}{ccc}4x-y=-15&\text{multiply both sides by (-2)}\\3x-2y=-10\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-8x+2y=30\\3x-2y=-10\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-5x=20\qquad\text{divide both sides by (-5)}\\.\qquad\qquad\boxed{x=-4}\\\\\\\text{Put the value of x to the first equation.}\\\\4(-4)-y=-15\\-16-y=-15\qquad\text{add 16 to both sides}\\-y=1\qquad\text{change the signs}\\\boxed{y=-1}$

5 0

3 years ago

Which side length will form an obtuse triangle with side lengths 8 and 10

Ne4ueva [31]

Answer:

Option J 13

Step-by-step explanation:

we know that

If applying the Pythagoras Theorem

$c^{2}> a^{2} +b^{2}$ ----> is an obtuse triangle

$c^{2}< a^{2} +b^{2}$ ----> is an acute triangle

$c^{2}= a^{2} +b^{2}$ ----> is a right triangle

where

c is the greater side

<em><u>Verify each case</u></em>

case F) we have

$c=10, a=6, b=8$

substitute

$10^{2}> 6^{2} +8^{2}$

$100> 100$ -----> is not true

Is a right triangle

case G) we have

$c=10, a=9, b=8$

substitute

$10^{2}> 9^{2} +8^{2}$

$100> 145$ -----> is not true

Is an acute triangle

case H) we have

$c=12, a=8, b=10$

substitute

$12^{2}> 8^{2} +10^{2}$

$144> 164$ -----> is not true

Is an acute triangle

case J) we have

$c=13, a=8, b=10$

substitute

$13^{2}> 8^{2} +10^{2}$

$169> 164$ -----> is true

Is an obtuse triangle

7 0

3 years ago