Solve each equation for d when c= 0 : -5d=2c +10

Nora ate x amount of strawberries. Zoe ate <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D" id="TexFormula1" title="\fra

aivan3 [116]

Answer:

B

Step-by-step explanation:

1/5 as a a decimal would be 0.20 because if you multiply 0.20 by 5 you get 1

6 0

3 years ago

Read 2 more answers

What is the ratio of 48 divided by 5:7

Rufina [12.5K]

I'll show you how I do it,hope you'll like it.
5:7, 5+7=12

5/12×48 =20
7/12×48=28

answer= 5:7
= 20:28
hope it helps.....

6 0

3 years ago

A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is la

Minchanka [31]

The exponential function which represented by the values in the table is $f(x)=4(\frac{1}{2})^{x}$ ⇒ 3rd answer

Step-by-step explanation:

The form of the exponential function is $f(x)=a(b)^{x}$ , where

a is the initial value (when x = 0)
b is the growth/decay factor
If k > 1, then it is a growth factor
If 0 < k < 1, then it is a decay factor

The table:

→ x : f(x)

→ -2 : 16

→ -1 : 8

→ 0 : 4

→ 1 : 2

→ 2 : 1

∵ $f(x)=a(b)^{x}$

- To find the exponential function substitute the value of x and f(x)

by some values from the table to find a and b, at first use the

point (0 , 4) to find the value of a

∵ x = 0 and f(x) = 4

∴ $4=a(b)^{0}$

- Remember that any number to the power of zero equal 1

except the zero

∵ $b^{0}=1$

∴ 4 = a(1)

∴ a = 4

Substitute the value of a in the equation

∴ $f(x)=4(b)^{x}$

- Chose any other point fro the table to find b, lets take (1 , 2)

∵ x = 1 and f(x) = 2

∴ $2=4(b)^{1}$

∴ 2 = 4 b

- Divide both sides by 4

∴ $b=\frac{2}{4}=\frac{1}{2}$

- Substitute the value of b in the equation

∴ $f(x)=4(\frac{1}{2})^{x}$

The exponential function which represented by the values in the table is $f(x)=4(\frac{1}{2})^{x}$

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

#LearnwithBrainly

8 0

3 years ago

Read 2 more answers

One cubic foot holds 7.48 gallons of water and one gallon of water weighs 8.33 pounds. How much does a cubic foot of water weigh

Ksivusya [100]

1 cubic foot = 7.48 gallons

1 gallon = 8.33 lbs

1 cubic foot (in lbs weight) = 7.48 gallons * 8.33 lbs = 62.3084 lbs = 62.3 lbs

1 lb = 16 oz

1 cubic foot water = 62.3084 lbs * 16 oz = 996.9344 is = 996.9 oz = 997 oz

6 0

4 years ago

Read 2 more answers

A class with n kids lines up for recess. The order in which the kids line up is random with eachordering being equally likely. T

Elis [28]

Answer:

A) P(Betty is first in line and mary is last) = P(B₁) + P(Mₙ) - (P(B₁) × P(Mₙ/B₁))

B) The method used is Relative frequency approach.

Step-by-step explanation:

From the question, we are told a sample of n kids line up for recess.

Now, the order in which they line up is random with each ordering being equally likely. Thus, this means that the probability of each kid to take a position is n(total of kids/positions).

Since we are being asked about 3 kids from the class, let's assign a letter to each kid:

J: John

B: Betty

M: Mary

A) Now, we want to find the probability that Betty is first in line or Mary is last in line.

In this case, the events are not mutually exclusive, since it's possible that "Betty is first but Mary is not last" or "Mary is last but Betty is not first" or "Betty is the first in line and Mary is last". Thus, there is an intersection between them and the probability is symbolized as;

P(B₁ ∪ Mₙ) = P(B₁) + P (Mₙ) - P(B₁ ∩ Mₙ) = P(B₁) + P(Mₙ) - (P(B₁) × P(Mₙ/B₁))

Where;

The suffix 1 refers to the first position while the suffix n refers to the last position.

Also, P(B₁ ∩ Mₙ) = P(B₁) × P(Mₙ/B₁)

This is because the events "Betty" and "Mary" are not independent since every time a kid takes his place the probability of the next one is affected.

B) The method used is Relative frequency approach.

In this method, the probabilities are usually assigned on the basis of experimentation or historical data.

For example, If A is an event we are considering, and we assume that we have performed the same experiment n times so that n is the number of times A could have occurred.

Also, let n_A be the number of times that A did occur.

Now, the relative frequency would be written as (n_A)/n.

Thus, in this method, we will define P(A) as:

P(A) = lim:n→∞[(n_A)/n]

7 0

4 years ago