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3 years ago

Solve for v. -5v = -3y + 4

Mathematics

2 answers:

seropon [69]3 years ago

7 0

Answer:

-5v + -3y + 4

the answer is V=3y/5 - 4/5

Margaret [11]3 years ago

3 0

To find this answer you must divide both side by -5 which will give you an answer of 3/5y - 4/5
ANSWER: 3/5y - 4/5

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A community pool that is shaped like a regular pentagon needs a new cover for the winter months. The radius of the pool is 20.10

boyakko [2]

Answer:

$960.42\text{ ft}^2$

Step-by-step explanation:

Please find the attachment.

We have been given that a community pool that is shaped like a regular pentagon needs a new cover for the winter months.

To find the area of community pool we will use area of pentagon formula.

$\text{Area of pentagon}=\frac{1}{2}a*p$ , where, a represents the apothem or perpendicular distance from the center of the pentagon and p represents perimeter of pentagon.

Let us find the perimeter of our given pentagon by multiplying each side length by 5.

$\text{Perimeter of community pool}=5\times 23.62$

$\text{Perimeter of community pool}=118.1$

Now let us find apothem of our pentagon by using Pythagoras theorem.

$a^2=20.10^2-11.81^2$

$a^2=404.01-139.4761$

$a^2=264.5339$

$a=\sqrt{264.5339}$

$a=16.2645$

Upon substituting our given values in above formula we will get,

$\text{Area of community pool}=\frac{1}{2}\times 16.2645\times 118.1$

$\text{Area of community pool}=8.13224907\times 118.1$

$\text{Area of community pool}=960.418615627971\approx 960.42$

Therefore, the area of the pool that needs to be covered is 960.42 square feet.

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3 years ago

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Randomly choose a tile without replacing the first tile you choose the second tile find the probability of the compound event wr

gayaneshka [121]

Answer:

Step-by-step explanation:

you have to do this first:

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2 years ago

How do I graph g(x)=f(x)+5

sashaice [31]

Find the absolute value vertex. In this case, the vertex for y=|x−5|y=|x-5| is (5,0)(5,0).

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(−∞,∞)(-∞,∞)

{x|x∈R}{x|x∈ℝ}

For each xx value, there is one yy value. Select few xx values from the domain. It would be more useful to select the values so that they are around the xx value of the absolute valuevertex.

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3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

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Temka [501]

Answer:

The answer is A

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