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3 years ago

PLEASE HELP! ! ! PLEASEEE!!

Mathematics

2 answers:

Molodets [167]3 years ago

4 0

Answer:

4^2

Step-by-step explanation:

4^4 times 4^3 is equal to 4^7 since you just add the exponents. Then, when dividing, you subtract the exponents, so 4^7/4^5 is 4^2. I hope this is helpful!

jasenka [17]3 years ago

4 0

Answer:

the answer is

Step-by-step explanation:

4 to the power of 2

you add 4 and 3 which is 7

and 7 subtract 5 which is

4 to the power of 2

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Please help will mark Brainliest!!

seraphim [82]

$~~~~~~x+80^{\circ} = 180^{\circ}\\\\\implies x = 180^{\circ} - 80^{\circ}\\\\\implies x = 100^{\circ}$

3 0

2 years ago

Coach Rivas can spend up to $750 on 30 swimsuits for the swim team. The inequality shown can be used to find the maximum amount

777dan777 [17]

Answer:

$0 < p ≤ $25

Step-by-step explanation:

We know that coach Rivas can spend up to $750 on 30 swimsuits.

This means that the maximum cost that the coach can afford to pay is $750, then if the cost for the 30 swimsuits is C, we have the inequality:

C ≤ $750

Now, if each swimsuit costs p, then 30 of them costs 30 times p, then the cost of the swimsuits is:

C = 30*p

Then we have the inequality:

30*p ≤ $750.

To find the possible values of p, we just need to isolate p in one side of the inequality.

So we can divide both sides by 30 to get:

(30*p)/30 ≤ $750/30

p ≤ $25

And we also should add the restriction:

$0 < p ≤ $25

Because a swimsuit can not cost 0 dollars or less than that.

Then the inequality that represents the possible values of p is:

$0 < p ≤ $25

6 0

3 years ago

Please help me!!! 30 minutes left

Lesechka [4]

Option D:

$\frac{25 a^{9} b^{10} }{6 }$ is equivalent to the given expression.

Solution:

Given expression:

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}$

To find which expression is equivalent to the given expression.

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}$

Using exponent rule: $(ab)^m=a^mb^m$

$$=\frac{5^3 a^3 b^{3}}{30 a^{-6} b^{-7}}$

Using exponent rule: $\frac{1}{a^{m}}=a^{-m}, \quad \frac{1}{a^{-m}}=a^{m}$

$$=\frac{125 a^3 b^{3}a^{6} b^{7}}{30 }$

$$=\frac{125 a^3 a^{6} b^{3} b^{7}}{30 }$

Using exponent rule: $a^{m} \cdot a^{n}=a^{m+n}$

$$=\frac{125 a^{3+6} b^{3+7} }{30 }$

$$=\frac{125 a^{9} b^{10} }{30 }$

Divide both numerator and denominator by the common factor 5.

$$=\frac{25 a^{9} b^{10} }{6 }$

$$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}=\frac{25 a^{9} b^{10} }{6 }$

Therefore, $\frac{25 a^{9} b^{10} }{6 }$ is equivalent to the given expression.

Hence Option D is the correct answer.

4 0

3 years ago

Cameron's uncle is 3 times old as he is. 4 years ago, he was 4 times older. How old is Cameron?

erma4kov [3.2K]

Let Cameron be x years old now.

Now:

Cameron = x

Uncle =3x

4 years ago:

Cameron = x - 4

Uncle = 3x - 4

4 years ago, Uncle is 4 times older:

3x - 4 = 4(x - 4)

Find x:

3x - 4 = 4(x - 4)

3x - 4 = 4x - 16

4x - 3x = 16 - 4

x = 12

Find the age:

Cameron = x = 12

Answer: Cameron is 12 years old now.

3 0

3 years ago

Read 2 more answers

Circles and segments create the many relationships addressed in the theorems throughout this unit. Use those theorems and the in

ohaa [14]

In your questions where the segment and circles create many relationship addressed in the theorem throughout this unit. So the following are the answers:
b.KI=5
c. EP = 2
e. CJ = 6
f.FH=14.4
g.AE=8.75

I hope you are satisfied with my answer

8 0

3 years ago