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kompoz [17]
3 years ago
5

F (n)=3+4 (n-1). find f(5) and f(6)

Mathematics
1 answer:
Rasek [7]3 years ago
5 0
3+16=19,

3+20=23

So the correct answer would be 19 and 23
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Please help!! <br>Find the number if intercepts of the graph of the function f(x)=x^2-2x+5​
hodyreva [135]

Answer: X does not intercept (none)                                                                                      

Y=(0,5)

Step-by-step explanation:

7 0
3 years ago
Two opposite sides of a rectangle are each of length x. If the perimeter of the rectangle is 12, then the area, as a function of
Reil [10]

Answer: x(6-x)

Step-by-step explanation:

Given : Two opposite sides of a rectangle are each of length x.

Let the other adjacent side be y.

The perimeter of the rectangle is 12 units.

Perimeter of rectangle is given by :-

P=2(\text{Sum of adjacent sides})\\\\\Rightarrow\ 12=2(x+y)\\\\\Rightarrow\ x+y=\dfrac{12}{2}=6\\\\\Rightarriow\ y=6-x

The area of rectangle is given by :-

A=\text{product of two adjacent sides}\\\\\Rightarrow\ A=xy=x(6-x)

Hence, the area as a function x = x(6-x)

7 0
3 years ago
Read 2 more answers
What is the algebraic expression of one fourth of a number n?
dybincka [34]
1/4n I think I hope this is correct
5 0
3 years ago
8. H={all numbers of the form 3n+1, for n a natural number} under multiplication?
poizon [28]

Answer and Step-by-step explanation:

H= {all numbers of the form 3n+1, for n natural number} under multiplication:

Sol: all number of the form 3n+1, for n natural number so, put n=2, 3(2) +1 = 7, which is a natural number. A natural number under multiplication does not form a group because its inverse does not exist.

J= {all number of the form 3n+2, for n natural number} under multiplication:

Sol: all the number of the form 3n+2, n is the natural number does not form a group under multiplication because the identity element does not form in this set, and inverse does not exist.

K= {perfect squares of integers} under addition:

Sol: perfect square of integers under addition does not form a group because the inverse does not exist. For example, for any element x, inverse (-x) does not exist because of a square integer.

L= {perfect squares of integers} under multiplication:

Sol: a set of the perfect square of integers under multiplication is not a set, because it does not have the inverse property

M= {all numbers of the form 2, for n natural number} under addition:

Sol: natural number in the form of 2n, n is a natural number under addition is not a group as it does not have identity property. Identity property, under addition, is zero.

N= {all number of the form 2n, n is natural number} under multiplication:

All number of the form 2n, n is the natural number under multiplication is not a group. Because its inverse does not exist. For example, an element x belongs to a natural number; its inverse (1/x) does not exist in this set.

8 0
3 years ago
What is the area of the circle below if it is 18 m
DiKsa [7]

Answer:

A≈1017.88 if r=18m or A≈254.47 if r=9

Step-by-step explanation:

A=Pi*r^2, plugging in 18 m or 9 m since lack of info but i assume you are giving 18m total length of circle, gives us answer.

6 0
4 years ago
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