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3 years ago

Q. # 13 please find the measure

Mathematics

2 answers:

lubasha [3.4K]3 years ago

6 0

The answer to your question would be 241° and this is the fourth option.

You will just multiply the angle, which 360 degrees since it is a circle, by 0.67
Solution:
360° * 0.67 = 241.2
= 241°

KATRIN_1 [288]3 years ago

5 0

The angle = 360° * 0.67 = 241.2

And by rounding to the nearest degree = 241°

The correct choice is number 4

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Kiko and mato each took out a loan for $5,000 from the bank. kika has an interest rate of 5.2% and he plans to repay the loan in

miv72 [106K]

It will be b : KikaKika 700:

Step-by-step explanation:

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1 year ago

A ruler measures length to the nearest 0.25 inches. which is the most appropriate way to report length using this ruler?

Travka [436]

Answer:

Report the length as x inches to the nearest quarter of an inch.

See the example below

Step-by-step explanation:

Report the length as x inches to the nearest quarter of an inch.

E.g : If the actual length is 2.4 inches then the reported length would be 2.5 in

Similarly if the actual length is 2.3 inches then the reported length would be 2.25 in

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3 years ago

X-23 / x^2 -x- 20 - 2/5-x

alexira [117]

By simplifying $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$ . This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$

Since two opposites add up to 0, remove them from the expression.

$- \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x$

Write all numerators above the least common denominator 5x2

$- \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}$

Use the commutative property to reorder the terms so that constants on the left

$\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}$

Rearrange the terms

$\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}$

By reording the terms

$- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$

Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

To learn more about simplifyication visit:

brainly.com/question/1542396

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7 0

1 year ago

SOMEONE PLEASE HELP WILL MARK BRAINLIEST

Mashutka [201]

Radical form for 112 would be 4{7 and then I think you can just search up how to reduce the 4 to 7 i don’t have the symbol btw

4 0

3 years ago

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

5 0

2 years ago