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3 years ago

7

Jane is one of 50 students to take a standardized math test that includes 100 multiple choice questions. If she has the highest

score of any student with a raw score of 87, what is her percentile score?

1 answer:

Pepsi [2]3 years ago

8 0

Answer: 87%
Solution:
87 correct questions over 100 = 87/100 = .87 = (change to percent by moving the decimal 2 places to the right) 87%

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You are studying for your final exam of the semester. up to this point,you recieved 3 exam scores of 76%,99%, and 86%. to reciev

Levart [38]

What you have to do is add up the amount of total grade scores. 76+99+86+x. You get 261+x. you have to get 99% or higher

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3 years ago

Read 2 more answers

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes

$\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}$

hence the answer is 0.4823

(iii) All are defective

$\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}$

(iv) At least one is defective

This is 1 - probability that none is defective

$\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}$

Hence the answer is 0.5177

3 0

10 months ago

Help please...........-

vovangra [49]

Answer:c

Step-by-step explanation:

c

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3 years ago

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Mike deposited $6500 into two saving accounts bearing simple interest. One of the accounts has an interest rate of 3% while the

ololo11 [35]

0.03x+0.06 (6500-x)=225
Solve for x
0.03x+390-0.06x=225
0.03x-0.06x=225-390
-0.03x=-165
X=165÷0.03
X=5500 invested at 3%

6500-5500=1000 invested at 6%

7 0

3 years ago

(5 Points)<br> all (1 – 3K)<br> -396<br> 0-374<br> 0 -198<br> 0 -187

Triss [41]

Answer:−3K−395,−374,−198,−187

Step-by-step explanation:

Remove parentheses.

1−3K−396,0−374,0−198,0−187

Simplify 1-3K-3961−3K−396 to -3K-395−3K−395.

−3K−395,0−374,0−198,0−187

Simplify 0-3740−374 to -374−374.

−3K−395,−374,0−198,0−187

Simplify 0-1980−198 to -198−198.

−3K−395,−374,−198,0−187

Simplify 0-1870−187 to -187−187.

−3K−395,−374,−198,−187

6 0

2 years ago