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Firlakuza [10]
4 years ago
7

Trey’s grandmother has a framed picture with side lengths that are 12 inches. Trey wants to know how much wall space is needed f

or the picture.
What is the area of a picture with side lengths that are 12 inches? Use the formula A= s^2, where s is the length of one side.
A. 12in.^2
B. 144in.^2
C. 24in.^2
D. 288in.^2
Mathematics
1 answer:
kipiarov [429]4 years ago
8 0

Answer:

B, 144in.^2 :)

Step-by-step explanation:

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Among the four northwestern states, Washington has 51% of the total population, Oregon has 30%, Idaho has 11%, and Montana has 8
morpeh [17]

Answer:

Step-by-step explanation:

H₀ : The distribution of the sample agrees with the population distribution.

H₁ : the distribution of the does not agree with the population distribution.

Using the  Chi-square test statistics

we will compute the expected frequencies

Now expected frequency for Washington will be

Fe = Npi = 1000×51% = 5100

expected frequency for Oregon

Fe = Npi = 1000×30% = 300

expected frequency for Idaho

Fe = Npi = 1000×11% = 110

expected frequency for  Montana

Fe = Npi = 1000×8% = 80

The Chi=square test statistics is;

x² = ∑ [ (Fo - Fe)² / Fe )

now we substitute

Given our Fo ( 450 in Washington, 340 in Oregon, 150 in Idaho, and 60 in Montana) from the question

x² =  (450-510)²/510 + (340-300)²/300 + (150-110)²/110 + (60-80)²/80

x²= 31.9376

so the chi-square test statistics is 31.9376

Now the chi-square critical value

first we compute for degree of freedom

d.f = k -1 = 4 - 1 = 3

So from the critical value table, degree of freedom 3 and significance level 0.05,

the chi-square critical value is 7.8147

Therefore chi-square test statistics 31.9376 is greater than the chi-square critical value 7.8147, so NULL HYPOTHESIS IS REJECTED at 5% significance.

There is sufficient evidence to warrant rejection  of the claim that the distribution of the sample agrees with the distribution of the state populations.

3 0
3 years ago
A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks
klio [65]

Answer:

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

So, the binomial probability distribution has two parameters, n and p.

In this problem, we have that n = 1000 and p = \frac{700}{1000} = 0.7. So the parameter is

a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.

8 0
3 years ago
The difference between 31 and a number is 7
astra-53 [7]

Answer:

thirty-eight

Step-by-step explanation:

31+7= answer

5 0
3 years ago
Read 2 more answers
Helppp please!
bagirrra123 [75]
He had 160$ when he first started
6 0
3 years ago
Find the area of the hexagon.<br> A) 36 in2 <br> B) 52 in2 <br> C) 78 in2 <br> D) 144 in2
s2008m [1.1K]

Answer: C) 78 in2

Step-by-step explanation:

The polygon is divided into two trapezoids with equal measurements.

Area of a trapezoid:

1

2

(b1 + b2)h

Since the area of the hexagon equals the area of two trapezoids with equal measurements, do not multiply by 1/2.

(b1 + b2)h

(10 + 16)3

26(3)

78 in2

4 0
3 years ago
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