Answer:
Yes
Step-by-step explanation:
Good luck
Answer:
The answer is 18p^3r and 63p^3
Step-by-step explanation:
G.C.F of 18p^3 r and 45p^4q is = 9p^3
18p^3r = 2*3*3*p*p*p*r
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
G.C.F of 63p^3 and 45p^4q is = 9p^3
63p^3 = 3*3*7*p*p*p
45p^4q = 3*3*5*p*p*p*q
Thus the G.C.F is 3*3*p*p*p = 9p^3
Therefore the answer is 18p^3r and 63p^3....
You would need to use the distance formula.
Distance = Sqrt((x2-x1)^2+(y2-y1)^2)
Plug in your numbers
Distance = Sqrt((12+4)^2+(12-18)^2)
Distance = 17.09
Answer:
Muercury 3
Venus 6
Mars 2
pluto 5
Jupiter 1
Nucleus4
Step-by-step explanation:
