Problem #1. (a) Prove that if z is irrational, then underroot x is irrational.
1 answer:
Answer with explanation:
It is given that z is an irrational complex number.
Z= x + i y
Where x is real part and y is Imaginary part.x and y can be any Real number.
If z is an irrational complex number , then both real part and imaginary part should be a complex number.That is x, y ∈Q, then ,Q= Set of Irrationals.
It means , x and y both should be an irrational number.
So, if x is any irrational number then, will be also an irrational number.
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Answer:
a
b
c
d
Step-by-step explanation:
Well lets look,
a)
If both slopes are different and have different y intercepts they have 1 solution.
So a has 1 solution
b)
Both slopes are different with different y intercepts.
1 solution
c)
Both slopes are different with different y intercepts
1 solution
d)
Different slopes different y intercepts
1 solution.
For proof look at the images below.
<em>Thus,</em>
<em>the answer is a,b,c, and d.</em>
<em>Hope this helps :)</em>
