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madam [21]
3 years ago
6

Mr. Patel is buying peaches at the grocery store.

Mathematics
2 answers:
aliina [53]3 years ago
7 0
Nearest tenth: 
3.9
Nearest whole number: 
4

When dealing with money, you must round up.
bogdanovich [222]3 years ago
6 0
The final answer is four
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Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF
Contact [7]

Find the equation of the inverse.

y =  {2}^{x + 5}  - 6

we have

y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6

step 1

Exchange the variables

x for y and y for x

x=\{2\}^{\{y+5\}}-6

step 2

Isolate the variable y

(x+6)=2^{(y+5)}

apply log both sides

\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\  \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}

step 3

Let

f^{(-1)}(x)=y

therefore

the inverse function is

f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5

7 0
1 year ago
Which equation could generate the curve in the graph below?y=3x^2-2x+1
4vir4ik [10]
If you are asking what is the graph of y = 3x^2 -2x+1.

Then, the attached file would be the answer.

To check, b^2 - 4(a)(c), for each equation and use these facts:

If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.

If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.

If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots. 

7 0
3 years ago
What is the solution for the equation 5/3b^3-2b^2-5=2/b^3-2
PilotLPTM [1.2K]
I looked it up and it said it was c 
7 0
3 years ago
Read 2 more answers
Find the domain and range of the following function ƒ(x) = 5|x - 2| + 4
Inessa [10]

Answer:

this is the answer fod this lroblsm

6 0
3 years ago
Find the lateral area of the cylinder. Give your answer in terms of pi
Artist 52 [7]

Answer:

<h2>204π units²</h2>

Step-by-step explanation:

The lateral area of the cylinder includes both the side and the ends.

The area of the side can be found by calculating the circumference of the cylinder and multiplying that by the height:  A = 2π(6 units )(11 units) = 132π units².

The area of one end of this cylinder can be found by applying the "area of a circle" formula:  A = πr².  Here, with r = 6 units, A = π(6 units)² = 36π units².  Since the cylinder has two ends, the total area of the ends is thus 2(36π units) = 72π units.

The total lateral area of the cylinder is thus 72π units² + 132π units², or 204π units²

7 0
3 years ago
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