Answer:
The perimeter of ΔABC = 12 units
Step-by-step explanation:
From the given triangle ABC on a coordinate plane, we can observe that:
The length of AB is the distance between A(1, 1) and B(4, 1)
so using the distance formula
- So the length of AB = 3 units
similarly the length of BC is the distance between B(4, 1) and C(4, 5)
- So the length of BC = 4 units
- As the length of of hypotenuse AC = 5 units
Therefore, the perimeter of the triangle ABC can be obtained using the formula:
P = AB + BC + AC
= 3 + 4 + 5
= 12 units
Therefore, the perimeter of ΔABC = 12 units