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Nostrana [21]
3 years ago
15

Write an equation for a line perpendicular to y=4x-5 and passing through the point (-12,1)

Mathematics
1 answer:
devlian [24]3 years ago
6 0

Answer:

y = -1/4x - 2

Step-by-step explanation:

Since the line has to be perpendicular, that means the new slope multiplied by the original should be -1. The original slope is 4, so the new one would be -1/4. Now our equation is y = -1/4x + z, z being the y intercept. We can find this by substituting the point in and finding the match. 1= -1/4(-12) + z. z has to equal -2, so the answer is y = -1/4x - 2

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172+(-167)+(-10)+(-144) what's the sum
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-149 would be your answer
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3 years ago
To the nearest tenth, find the perimeter of ∆ABC with vertices A(-1,4), B(-2,1) and C(2,1). Show your work.
frez [133]

Answer: \bold{4+3\sqrt2+\sqrt{10}}

<u>Step-by-step explanation:</u>

Perimeter is the sum of the lengths of the sides.  Use the distance formula to find the lengths of each of the sides, then find their sum.

d_{AB}=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}

     =\sqrt{(-2+1)^2+(1-4)^2}

     =\sqrt{(-1)^2+(-3)^2}

     =\sqrt{1+9}

     =\sqrt{10}

d_{AC}=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}

     =\sqrt{(2+1)^2+(1-4)^2}

     =\sqrt{(3)^2+(-3)^2}

     =\sqrt{9+9}

     =\sqrt{18}

     =3\sqrt{2}

d_{BC}=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}

     =\sqrt{(2+2)^2+(1-1)^2}

     =\sqrt{(4)^2+(0)^2}

     =\sqrt{16+0}

     =\sqrt{16}

     =4

8 0
4 years ago
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s344n2d4d5 [400]
The answer is at the end of turn 3.
7 0
3 years ago
What is five hundred six and twelve hundredths in standard form
Trava [24]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ Five hundred six and twelve hundredths in standard form is 506.12

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

5 0
3 years ago
The product of two numbers decreased by six is less than 30. Write an algebraic expression, but do not solve. *
Jlenok [28]

Answer:

(x × y) - 6 < 30

xy - 6 < 30

xy < 30 + 6

xy < 36

Step-by-step explanation:

Let us represent:

First number = x

Second number = y

The product of two numbers decreased by six is less than 30.

The algebraic expression is given as

(x × y) - 6 < 30

xy - 6 < 30

xy < 30 + 6

xy < 36

6 0
3 years ago
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