Answer:
The two requirements for something to be matter are
1. Mass
2. Volume
Because we do or we would die
Answer:
8 chromosomes
Explanation:
Diploid state is when an organism have two set of chromosomes (2n) i.e. combination of two haploid (n) gametes containing one set of chromosome each. Sexually reproducing organisms whose somatic or body cells are diploid (2n) undergo meiosis to produce gametes or sex cells with haploid number (n).
Therefore, in the newly discovered Biologica terificia species of snail, if the haploid state (n) of their gametes is 4, then their diploid (2n) somatic cells must be 4 × 2 = 8.
The question specifies the chromosomal number at the G1 phase of Interphase. At this stage, the cell is preparing to undergo division by increasing in size and duplicating its organnelles but not yet its genetic material which is not until the next phase called S-phase. Hence, the chromosome number of somatic cells remain 8 at the G1 phase.
Answer: 1/4
Explanation:
Firstly, in order for both parents to be type A and have children with type o blood, their blood types must both be Ao. Since o is a recessive blood type, a punnett square shows there is a 25% chance any child of theirs will have type o blood. If neither parent is color blind and they have a son who is, it implies that the mother is a carrier of colorblindness and has the genotype XᴮXᵇ. If you do a punnett square of the not colorblind father (XᴮY) and the mother, it shows that a daughter would have a 0% chance of being colorblind. Therefore colorblindess is irrelevent, since there is no possibility of the daughter not having normal color vision. In conclusion, there's a 25% chance she will have type o blood and not be colorblind, since the other 75% chance would be having type A blood and not being colorblind.
