Answer:
yes alby is correct
Step-by-step explanation:
Given:
a grid 2/3 of the squares are shaded with color.
And 1/4 of the squares on the grid is shaded blue
So, to Find the fraction of the Shaded squares are blue squares
Multiply both fractions
So,
so, the answer will be 1/6 of the Shaded squares are blue squares
Answer:
The suitable results are:
Option A: The alternative hypothesis could really be true but because the sample size is small, the power is very low so the researchers are likely to run an experiment whose results lead them to make a type II error.
Option D: Inasmuch there is no statistical evidence to accept the null hypothesis. The null hypothesis could be true and there is no difference between the new and standard treatments survival rate.
Explanation:
Below are the options suitable for results:
Option A: The alternative hypothesis could really be true but because the sample size is small, the power is very low so the researchers are likely to run an experiment whose results lead them to make a type II error - Reason been that, as the sample size increase, so also does the power of the test increase. Therefore, because the power is too small, the researchers are likely to commit type 2 error.
Option D: Inasmuch there is no statistical evidence to accept the null hypothesis. The null hypothesis could be true and there is no difference between the new and standard treatments survival rate.
Answer: don't know sorry
Step-by-step explanation:
Look for an integrating factor 
:
Multiply both sides by 
:
Condense the left side as the derivative of a product:
![\dfrac{\mathrm d}{\mathrm dt}\left[(t+1)^{-7/9}y\right]=\dfrac{14}9t(t+1)^{-16/9}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dt%7D%5Cleft%5B%28t%2B1%29%5E%7B-7%2F9%7Dy%5Cright%5D%3D%5Cdfrac%7B14%7D9t%28t%2B1%29%5E%7B-16%2F9%7D)
Integrate both sides:
For the integral on the right, substitute
Given that 
, we get
