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statuscvo [17]
4 years ago
6

Please help, I have an algebra test tomorrow and i'm trying to understand problems like this.

Mathematics
1 answer:
Sonja [21]4 years ago
3 0

Answer:

L=P/2-W

Step-by-step explanation:

P=2(L+w) - Solve for L

1) Use the distributive property on the right side of the equation:

P=2L+2w

2) Subtract both sides by 2w:

P-2w=2L

3) Divide both sides by 2 to Isolate L:

P/2-W=L

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The function ƒ(x) = (x − 1)^2 + 5 is not one-to-one. Find a portion of the domain where the function is one-to-one and find an i
melisa1 [442]

Answer:

f(x)=(x-1)^2+5 with domain x>1 and range y>5 has inverse g(x)=sqrt(x-5)+1 with domain x>5 and range y>1.

Step-by-step explanation:

The function is a parabola when graphed. It is in vertex form f(x)=a(x-h)^2+k where (h,k) is vertex and a tells us if it's reflected or not or if it's stretched. The thing we need to notice is the vertex because if we cut the graph with a vertical line here the curve will be one to one. So the vertex is (1,5). Let's restrict the domain so x >1.

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* Also since the parabola opens up, then y>5.

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This is what i got, i hope i understood the question correctly.v
6 0
3 years ago
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