Question 1: In both questions, we have to find the repeating decimal as a fraction. There is a specific way to find the fraction given a repeated decimal. In our equation, our variable x will represent the fraction.

x=0.272727....

If you know how too solve systems of equations by elimination, we need to to do something similar to eliminate all of the repeating parts so we can solve for x.

We need to make this a number greater than zero but line up the digits so that we can eliminate every single repeating digit.

To do this, we move the digit as many times to the right as there are digits that repeat. In this case, there are two repeating digits, so we multiply the whole equation by 100.

100x=27.2727...

Now, we can subtract the first equation from the second so that the repeating parts are removed and we can then solve for x and find our fraction.

99x=27

Now, we solve for x.

x=27/99

Now we subtract this from the first fraction.

11/6-27/99= 1 37/66

To make this into a repeating decimal, we just divide the numerator by the denominator.

1.560606060...

As we can see, the 60 is repeating, so the answer is the second option on the first one.

Question 2: In this case, we have two repeating decimals. Let's solve for them both. Because we have a digit after the decimal that does not repeat, we need to move it before we subtract.

10x=4.090909...

We need to line up the decimals, and in this case we need to multiply by 1000.

990x=409.090909...

Now we subtract...

990x=405

We solve...

x=9/22

Now we do the other one.

10x=6.81818181...

We multiply by 100 to line up the decimals for subtraction.

1000x=681.8181....

We subtract...

990x=675

x=15/22

Now, we add our fractions.

24/22 or 1 2/22

Now we turn it back into a repeating.

24/22= 1.09090909...

For this question, select the second option.

I hope this helps!

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3 years ago