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Marina CMI [18]
4 years ago
14

Solve the equation and check your answer. 0.95 t plus 0.05 left parenthesis 100 minus t right parenthesis equals 0.49 left paren

thesis 100 right parenthesis
Mathematics
1 answer:
Triss [41]4 years ago
7 0
<h2>Answer:</h2>

The value of t is:

                     t=48.8889

<h2>Step-by-step explanation:</h2>

We are asked to solve the linear equation in terms of variable t.

The equation is given by:

0.95t+0.05(100-t)=0.49(100)

Firstly we will solve the parentheses term in the left and right hand side of the equality as follows:

0.95t+0.05\times 100-0.05t=49

Now we combine the like terms on the left side of equality by:

0.95t-0.05t+5=49\\\\i.e.\\\\0.90t+5=49

Now we subtract both side of the equation by 5 to get:

0.90t=44

Now on dividing both side of the equation by 0.90 we get:

t=\dfrac{44}{0.90}\\\\i.e.\\\\t=48.8889

Hence, the value of t is:   48.8889

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Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

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Coordinates of D =(-2,-3)

Distance formula :d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}

AB=7.21 unit

B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}

BC=6

C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}

CD=7.21

A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}

AD=6

A=(x_1,y_1)=(-2,3)\\C=(x_2,y_2)=(2,3)

AC=\sqrt{(2+2)^2+(3-3)^2}

AC=4

B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)

BD=\sqrt{(-2-2)^2+(-3+3)^2}

BD=4

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